Q:

Write an equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5). A) y = -2x + 15 B) y = 2x - 15 C) y = -2x - 5 D) y = - 1/2x

Accepted Solution

A:
Answer:the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)= -5 = -2x + 15Step-by-step explanation:Write an equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5).Using the slope intercept equation,y = mx +cm = slope = 1/2For two lines to be perpendicular, the product of their slopes is -1Let the slope of the other line be m2m1×m2 =-11/2×m2 = -1m2 = -1/(1/2) = -2Slope of line = -2For points (10, -5), x = 10, y =-5-5 = -2× 10 +c-5 = -20+ c c = -5+20= 15the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)-5 = -2x + 15