MATH SOLVE

3 months ago

Q:
# Find the LARGEST of three consecutive integers such that 3 times the sum of the first and the third integer is equal to 30 more than 4 times the second integer.

Accepted Solution

A:

Answer:

The largest would be 16 (the other two would be 14, 15).

Explanation:

Solve this by:

1- setting the first equal to x, the second to x+1 and the third to x+2.

2- write the equation given the description.

3(x+x+2) = 4(x+1) + 30.

3- solve.

3x + 3x + 6 = 4x + 4 + 30.

6x + 6 = 4x + 34.

2x = 28.

x =14

The largest would be 16 (the other two would be 14, 15).

Explanation:

Solve this by:

1- setting the first equal to x, the second to x+1 and the third to x+2.

2- write the equation given the description.

3(x+x+2) = 4(x+1) + 30.

3- solve.

3x + 3x + 6 = 4x + 4 + 30.

6x + 6 = 4x + 34.

2x = 28.

x =14